document.write( "Question 399700: The larger of two consecutive intergers is 10 more than twice the smaller. Find the intergers. \n" ); document.write( "

Algebra.Com's Answer #283035 by Tatiana_Stebko(1539) $\"\"$ $\"About$

You can put this solution on YOUR website!
if the first integer is x, then the second is (x+1) (because they are two consecutive integers).
\n" ); document.write( "The larger of two consecutive integers((x+1)) is 10 more than twice the smaller (x) we can write in this way: $\"x%2F2=%28x%2B1%29-10\"$
\n" ); document.write( " $\"x%2F2=x%2B1-10\"$
\n" ); document.write( " $\"x%2F2-x=-9\"$
\n" ); document.write( " $\"-x%2F2=-9\"$
\n" ); document.write( " $\"x=18\"$ the smaller integer
\n" ); document.write( " $\"x%2B1=18%2B1=19\"$ the larger integer
\n" ); document.write( "Answer 18, 19 \n" ); document.write( "

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