document.write( "Question 43154: The profit earned from manufacturing x widgets is .0001x3 - .21x2 + 135x - 2000 dollars. Other contraints dictate that at least 200 widegets but no more than 950 widgets be manufactured.
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document.write( "How many widgets should be produced to earn the maximum profit?\r
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document.write( " a. 950
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document.write( " b. 17400
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document.write( " c. 500
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document.write( " d. 25500
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document.write( " e. None of the others \n" );
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Algebra.Com's Answer #28301 by venugopalramana(3286)![]() ![]() You can put this solution on YOUR website! The profit earned from manufacturing x widgets is \n" ); document.write( "P= .0001x3 - .21x2 + 135x - 2000 ..HOPE YOU KNOW DIFFERENTIATION \n" ); document.write( "DP/DX=0.0001*3X^2-0.21*2X+135=0...FOR P TO HAVE AN EXTREMUM \n" ); document.write( "=0.0003X^2-0.42X+135=0 \n" ); document.write( "X=(0.42+ OR - 0.12)/(2*0.0003) \n" ); document.write( "=900 OR 500 \n" ); document.write( "D^2P/DX^2=0.0006X-0.42....AT X=900,WE GET...0.0006*900-0.42=0.12....HENCE MINIMUM \n" ); document.write( "AT X=500,WE GET....0.0006*500-0.42=-0.12....HENCE MAXIMUM \n" ); document.write( "SO X=500 IS CORRECT ANSWER...C IS CORRECT\r \n" ); document.write( "\n" ); document.write( "dollars. Other contraints dictate that at least 200 widegets but no more than 950 widgets be manufactured. \n" ); document.write( "How many widgets should be produced to earn the maximum profit? \n" ); document.write( "a. 950 \n" ); document.write( "b. 17400 \n" ); document.write( "c. 500 \n" ); document.write( "d. 25500 \n" ); document.write( "e. None of the others \n" ); document.write( " |