document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=399420>Question 399420</A>: <I><SPAN STYLE=\"word-break: break-all;\"> solve for x: sin(2x-3) csc(5x-15)=1 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #282865 by </B><A HREF=/tutors/aboutme.mpl?userid=CharlesG2><B>CharlesG2(834)</B></A><img src=\"/images/stars/stars-11.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=CharlesG2><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=282865\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> solve for x: sin(2x-3) csc(5x-15)=1\r<BR>\n" );
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document.write( "csc = 1/sin<BR>\n" );
document.write( "sin(2x - 3)csc(5x - 15) = 1<BR>\n" );
document.write( "sin(2x - 3)/sin(5x - 15) = 1<BR>\n" );
document.write( "sin(2x - 3) = sin(5x - 15)<BR>\n" );
document.write( "2x - 3 must equal 5x - 15<BR>\n" );
document.write( "2x - 3 = 5x - 15<BR>\n" );
document.write( "-3x = -12<BR>\n" );
document.write( "x = -12/-3 = 12/3 = 4<BR>\n" );
document.write( " </SPAN>\n" );
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