document.write( "Question 399387: 1. What is the equation of a line that passes through points (-1, 2) and (5, 2)?
\n" ); document.write( "y - 2 = 0
\n" ); document.write( "x - 2 = 0
\n" ); document.write( "y - x - 2 = 0\r
\n" ); document.write( "\n" ); document.write( "2. What is the equation of a line with a slope of -2 and a y-intercept of 8?
\n" ); document.write( "x + 2y - 8 = 0
\n" ); document.write( "2x + y - 8 = 0
\n" ); document.write( "2x - y + 8 = 0\r
\n" ); document.write( "\n" ); document.write( "3. What is the slope of a line parallel to the line whose equation is y - x = 5?
\n" ); document.write( "-1
\n" ); document.write( "1
\n" ); document.write( "5\r
\n" ); document.write( "\n" ); document.write( "4. What is the equation of the line that passes through the point (1, 1) and has a y-intercept of 2.
\n" ); document.write( "x - y + 2 = 0
\n" ); document.write( "x + y - 2 = 0
\n" ); document.write( "x - y - 2 = 0\r
\n" ); document.write( "\n" ); document.write( "5. The slope of a line is 1/3 . What is the slope of a line perpendicular to this line?
\n" ); document.write( "-3
\n" ); document.write( "-1/3
\n" ); document.write( "1/3
\n" ); document.write( "3\r
\n" ); document.write( "\n" ); document.write( "6. What is the slope of a line perpendicular to the line whose equation is y = 2x + 5?
\n" ); document.write( "slope = -1
\n" ); document.write( "slope = -1/2
\n" ); document.write( "slope = -2\r
\n" ); document.write( "\n" ); document.write( "7. What is the equation of a line with a point (-3, 0) and no slope?
\n" ); document.write( "x + 3 = 0
\n" ); document.write( "y + 3 = 0
\n" ); document.write( "x - 3 = 0
\n" ); document.write( "y - 3 = 0\r
\n" ); document.write( "\n" ); document.write( "8. What is the equation of a line that passes through point (1, -2) and has a slope of 1/3 .
\n" ); document.write( "3x - y - 7 = 0
\n" ); document.write( "x - 3y + 7 = 0
\n" ); document.write( "x - 3y - 7 = 0\r
\n" ); document.write( "\n" ); document.write( "9. What is the equation of the line whose y-intercept is 3 and slope is 1?
\n" ); document.write( "y = x - 3
\n" ); document.write( "y = x + 3
\n" ); document.write( "y = 3x + 1
\n" ); document.write( "

Algebra.Com's Answer #282840 by MathLover1(20849)\"\" \"About 
You can put this solution on YOUR website!
1.\r
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Solved by pluggable solver: Finding the Equation of a Line
First lets find the slope through the points (\"-1\",\"2\") and (\"5\",\"2\")
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\n" ); document.write( " \"m=%28y%5B2%5D-y%5B1%5D%29%2F%28x%5B2%5D-x%5B1%5D%29\" Start with the slope formula (note: (\"x%5B1%5D\",\"y%5B1%5D\") is the first point (\"-1\",\"2\") and (\"x%5B2%5D\",\"y%5B2%5D\") is the second point (\"5\",\"2\"))
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\n" ); document.write( " \"m=%282-2%29%2F%285--1%29\" Plug in \"y%5B2%5D=2\",\"y%5B1%5D=2\",\"x%5B2%5D=5\",\"x%5B1%5D=-1\" (these are the coordinates of given points)
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\n" ); document.write( " \"m=+0%2F6\" Subtract the terms in the numerator \"2-2\" to get \"0\". Subtract the terms in the denominator \"5--1\" to get \"6\"
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\n" ); document.write( " \"m=0\" Reduce
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\n" ); document.write( " So the slope is
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\n" ); document.write( " \"m=0\"
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\n" ); document.write( "Now let's use the point-slope formula to find the equation of the line:
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\n" ); document.write( " ------Point-Slope Formula------
\n" ); document.write( " \"y-y%5B1%5D=m%28x-x%5B1%5D%29\" where \"m\" is the slope, and (\"x%5B1%5D\",\"y%5B1%5D\") is one of the given points
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\n" ); document.write( " So lets use the Point-Slope Formula to find the equation of the line
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\n" ); document.write( " \"y-2=%280%29%28x--1%29\" Plug in \"m=0\", \"x%5B1%5D=-1\", and \"y%5B1%5D=2\" (these values are given)
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\n" ); document.write( " \"y-2=%280%29%28x%2B1%29\" Rewrite \"x--1\" as \"x%2B1\"
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\n" ); document.write( " \"y-2=0x%2B%280%29%281%29\" Distribute \"0\"
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\n" ); document.write( " \"y-2=0x%2B0\" Multiply \"0\" and \"1\" to get \"0%2F0\". Now reduce \"0%2F0\" to get \"0\"
\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( " \"y=0x%2B0%2B2\" Add \"2\" to both sides to isolate y
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\n" ); document.write( " \"y=0x%2B2\" Combine like terms \"0\" and \"2\" to get \"2\"
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\n" ); document.write( " Answer:
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\n" ); document.write( " So the equation of the line which goes through the points (\"-1\",\"2\") and (\"5\",\"2\") is:\"y=0x%2B2\"
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\n" ); document.write( " The equation is now in \"y=mx%2Bb\" form (which is slope-intercept form) where the slope is \"m=0\" and the y-intercept is \"b=2\"
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\n" ); document.write( " Notice if we graph the equation \"y=0x%2B2\" and plot the points (\"-1\",\"2\") and (\"5\",\"2\"), we get this: (note: if you need help with graphing, check out this solver)
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\n" ); document.write( " Graph of \"y=0x%2B2\" through the points (\"-1\",\"2\") and (\"5\",\"2\")
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\n" ); document.write( " Notice how the two points lie on the line. This graphically verifies our answer.
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\n" ); document.write( "\n" ); document.write( "answer: \"y+-+x+-+2+=+0\" or in slope-intercept form \"y+=+x+%2B+2\"\r
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\n" ); document.write( "\n" ); document.write( "2.\r
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Solved by pluggable solver: FIND a line by slope and one point

\n" ); document.write( " What we know about the line whose equation we are trying to find out:
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    \n" ); document.write( "
  • it goes through point (0, 8)

  • \n" ); document.write( "
  • it has a slope of -2

  • \n" ); document.write( "

\n" ); document.write( "
\n" ); document.write( " First, let's draw a diagram of the coordinate system with point (0, 8) plotted with a little blue dot:
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\n" ); document.write( "
\n" ); document.write( " Write this down: the formula for the equation, given point \"x%5B1%5D%2C+y%5B1%5D\" and intercept a, is
\n" ); document.write( "
\n" ); document.write( " \"y=ax+%2B+%28y%5B1%5D-a%2Ax%5B1%5D%29\" (see a paragraph below explaining why this formula is correct)
\n" ); document.write( "
\n" ); document.write( " Given that a=-2, and \"system%28+x%5B1%5D+=+0%2C+y%5B1%5D+=+8+%29+\", we have the equation of the line:
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\n" ); document.write( " \"y=-2%2Ax+%2B+8\"
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\n" ); document.write( " Explanation: Why did we use formula \"y=ax+%2B+%28y%5B1%5D+-+a%2Ax%5B1%5D%29\" ? Explanation goes here. We are trying to find equation y=ax+b. The value of slope (a) is already given to us. We need to find b. If a point (\"x%5B1%5D\", \"y%5B1%5D\") lies on the line, it means that it satisfies the equation of the line. So, our equation holds for (\"x%5B1%5D\", \"y%5B1%5D\"): \"y%5B1%5D+=+a%2Ax%5B1%5D%2Bb\" Here, we know a, \"x%5B1%5D\", and \"y%5B1%5D\", and do not know b. It is easy to find out: \"b=y%5B1%5D-a%2Ax%5B1%5D\". So, then, the equation of the line is: \"+y=ax%2B%28y%5B1%5D-a%2Ax%5B1%5D%29+\".
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\n" ); document.write( " Here's the graph:
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\n" ); document.write( "\n" ); document.write( "answer: \"2x+%2B+y+-+8+=+0\" or in slope-intercept form \"y+=-2x%2B8\"\r
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\n" ); document.write( "\n" ); document.write( "3.\r
\n" ); document.write( "\n" ); document.write( "\"y+-+x+=+5\" or \"-+x+%2B+y+=+5\"\r
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Solved by pluggable solver: DESCRIBE a linear EQUATION: slope, intercepts, etc
Equation \"-1+x+%2B+1+y+=+5\" describes a sloping line. For any
\n" ); document.write( " equation ax+by+c = 0, slope is \"-a%2Fb+=+--1%2F1\".
  • X intercept is found by setting y to 0: ax+by=c becomes ax=c. that means that x = c/a. 5/-1 = -5.
  • Y intercept is found by setting x to 0: the equation becomes by=c, and therefore y = c/b. Y intercept is 5/1 = 5.
  • Slope is --1/1 = 1.
  • Equation in slope-intercept form: y=1*x+5.
\"graph%28+500%2C+500%2C+-5-8%2C+-5%2B8%2C+5-8%2C+5%2B8%2C+1%2Ax%2B5+%29+\"\n" ); document.write( "

\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "answer: slope is \"-a%2Fb=+-%28-1%29%2F1=1\"\r
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\n" ); document.write( "\n" ); document.write( "4.\r
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Solved by pluggable solver: FIND EQUATION of straight line given 2 points
hahaWe are trying to find equation of form y=ax+b, where a is slope, and b is intercept, which passes through points (x1, y1) = (1, 1) and (x2, y2) = (0, 2).
\n" ); document.write( " Slope a is \"a+=+%28y%5B2%5D-y%5B1%5D%29%2F%28x%5B2%5D-x%5B1%5D%29+=+%282-1%29%2F%280-1%29+=+-1\".
\n" ); document.write( " Intercept is found from equation \"a%2Ax%5B1%5D%2Bb+=+y%5B1%5D\", or \"-1%2A1+%2Bb+=+2\". From that,
\n" ); document.write( " intercept b is \"b=y%5B1%5D-a%2Ax%5B1%5D\", or \"b=1--1%2A1+=+2\".
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\n" ); document.write( " y=(-1)x + (2)
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\n" ); document.write( " Your graph:
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\n" ); document.write( "\n" ); document.write( "answer: \"x+%2B+y+-+2+=+0\"or in slope-intercept form \"y+=-x%2B2\"\r
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\n" ); document.write( "\n" ); document.write( "5.\r
\n" ); document.write( "\n" ); document.write( "if slope of the one line is \"m\", the slope of perpendicular line will be \"m1=-%281%2Fm%29\"\r
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\n" ); document.write( "\n" ); document.write( "so, if \"m=1%2F3\", the slope of perpendicular line will be \"m1=-%281%2F%281%2F3%29%29=-3\"\r
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\n" ); document.write( "\n" ); document.write( "6.\r
\n" ); document.write( "\n" ); document.write( "equation \"+y+=+2x+%2B+5\" is already in slope-intercept form and you can see that slope is \"2\"; so, the slope of a line perpendicular to this line will be \"-%281%2F2%29\" \r
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\n" ); document.write( "\n" ); document.write( "7.\r
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Solved by pluggable solver: FIND a line by slope and one point

\n" ); document.write( " What we know about the line whose equation we are trying to find out:
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  • it goes through point (-3, 0)

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  • it has a slope of 0

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\n" ); document.write( " First, let's draw a diagram of the coordinate system with point (-3, 0) plotted with a little blue dot:
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\n" ); document.write( " Write this down: the formula for the equation, given point \"x%5B1%5D%2C+y%5B1%5D\" and intercept a, is
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\n" ); document.write( " \"y=ax+%2B+%28y%5B1%5D-a%2Ax%5B1%5D%29\" (see a paragraph below explaining why this formula is correct)
\n" ); document.write( "
\n" ); document.write( " Given that a=0, and \"system%28+x%5B1%5D+=+-3%2C+y%5B1%5D+=+0+%29+\", we have the equation of the line:
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\n" ); document.write( " \"y=0%2Ax+%2B+0\"
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\n" ); document.write( " Explanation: Why did we use formula \"y=ax+%2B+%28y%5B1%5D+-+a%2Ax%5B1%5D%29\" ? Explanation goes here. We are trying to find equation y=ax+b. The value of slope (a) is already given to us. We need to find b. If a point (\"x%5B1%5D\", \"y%5B1%5D\") lies on the line, it means that it satisfies the equation of the line. So, our equation holds for (\"x%5B1%5D\", \"y%5B1%5D\"): \"y%5B1%5D+=+a%2Ax%5B1%5D%2Bb\" Here, we know a, \"x%5B1%5D\", and \"y%5B1%5D\", and do not know b. It is easy to find out: \"b=y%5B1%5D-a%2Ax%5B1%5D\". So, then, the equation of the line is: \"+y=ax%2B%28y%5B1%5D-a%2Ax%5B1%5D%29+\".
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\n" ); document.write( " Here's the graph:
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\n" ); document.write( "\n" ); document.write( "8.\r
\n" ); document.write( "\n" ); document.write( "the equation of a line that passes through point (1, -2) and has a slope of 1/3 \r
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Solved by pluggable solver: FIND a line by slope and one point

\n" ); document.write( " What we know about the line whose equation we are trying to find out:
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    \n" ); document.write( "
  • it goes through point (1, -2)

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  • it has a slope of 0.333333333333333

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\n" ); document.write( "
\n" ); document.write( " First, let's draw a diagram of the coordinate system with point (1, -2) plotted with a little blue dot:
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\n" ); document.write( " Write this down: the formula for the equation, given point \"x%5B1%5D%2C+y%5B1%5D\" and intercept a, is
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\n" ); document.write( " \"y=ax+%2B+%28y%5B1%5D-a%2Ax%5B1%5D%29\" (see a paragraph below explaining why this formula is correct)
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\n" ); document.write( " Given that a=0.333333333333333, and \"system%28+x%5B1%5D+=+1%2C+y%5B1%5D+=+-2+%29+\", we have the equation of the line:
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\n" ); document.write( " \"y=0.333333333333333%2Ax+%2B+-2.33333333333333\"
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\n" ); document.write( " Explanation: Why did we use formula \"y=ax+%2B+%28y%5B1%5D+-+a%2Ax%5B1%5D%29\" ? Explanation goes here. We are trying to find equation y=ax+b. The value of slope (a) is already given to us. We need to find b. If a point (\"x%5B1%5D\", \"y%5B1%5D\") lies on the line, it means that it satisfies the equation of the line. So, our equation holds for (\"x%5B1%5D\", \"y%5B1%5D\"): \"y%5B1%5D+=+a%2Ax%5B1%5D%2Bb\" Here, we know a, \"x%5B1%5D\", and \"y%5B1%5D\", and do not know b. It is easy to find out: \"b=y%5B1%5D-a%2Ax%5B1%5D\". So, then, the equation of the line is: \"+y=ax%2B%28y%5B1%5D-a%2Ax%5B1%5D%29+\".
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\n" ); document.write( " Here's the graph:
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\n" ); document.write( "\n" ); document.write( "you got:\r
\n" ); document.write( "\n" ); document.write( "\"3x+-+y+-+7+=+0\"...or in slope-intercept form \"y=3x-7\"\r
\n" ); document.write( "\n" ); document.write( "\"x+-+3y+%2B+7+=+0\"...or in slope-intercept form \"3y=-x-7\" \r
\n" ); document.write( "\n" ); document.write( "or\"y=-%281%2F3%29x-7%2F3\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"x+-+3y+-+7+=+0+\"...or in slope-intercept form \"3y=x-7\" or\"y=%0D%0A%0D%0A%281%2F3%29x-7%2F3\"\r
\n" ); document.write( "\n" ); document.write( "so the answer is : \"y=%281%2F3%29x+-+7%2F3\"\r
\n" ); document.write( "\n" ); document.write( "9.\r
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Solved by pluggable solver: FIND a line by slope and one point

\n" ); document.write( " What we know about the line whose equation we are trying to find out:
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  • it goes through point (0, 3)

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  • it has a slope of 1

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\n" ); document.write( "
\n" ); document.write( " First, let's draw a diagram of the coordinate system with point (0, 3) plotted with a little blue dot:
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\n" ); document.write( "
\n" ); document.write( " Write this down: the formula for the equation, given point \"x%5B1%5D%2C+y%5B1%5D\" and intercept a, is
\n" ); document.write( "
\n" ); document.write( " \"y=ax+%2B+%28y%5B1%5D-a%2Ax%5B1%5D%29\" (see a paragraph below explaining why this formula is correct)
\n" ); document.write( "
\n" ); document.write( " Given that a=1, and \"system%28+x%5B1%5D+=+0%2C+y%5B1%5D+=+3+%29+\", we have the equation of the line:
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\n" ); document.write( " \"y=1%2Ax+%2B+3\"
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\n" ); document.write( " Explanation: Why did we use formula \"y=ax+%2B+%28y%5B1%5D+-+a%2Ax%5B1%5D%29\" ? Explanation goes here. We are trying to find equation y=ax+b. The value of slope (a) is already given to us. We need to find b. If a point (\"x%5B1%5D\", \"y%5B1%5D\") lies on the line, it means that it satisfies the equation of the line. So, our equation holds for (\"x%5B1%5D\", \"y%5B1%5D\"): \"y%5B1%5D+=+a%2Ax%5B1%5D%2Bb\" Here, we know a, \"x%5B1%5D\", and \"y%5B1%5D\", and do not know b. It is easy to find out: \"b=y%5B1%5D-a%2Ax%5B1%5D\". So, then, the equation of the line is: \"+y=ax%2B%28y%5B1%5D-a%2Ax%5B1%5D%29+\".
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\n" ); document.write( " Here's the graph:
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\n" ); document.write( "\n" ); document.write( "so the answer is : \"y+=+x+%2B+3\"\r
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