document.write( "Question 399354: The perimeter of a rectangle is 70 cm. The length of the rectangle is 4 cm less than double the width. Find the length and width of the rectangle \n" ); document.write( "
Algebra.Com's Answer #282783 by mananth(16946)\"\" \"About 
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let width =x
\n" ); document.write( "length = 2x-4
\n" ); document.write( "perimeter = 70
\n" ); document.write( "..
\n" ); document.write( "2*(L+W)=perimeter
\n" ); document.write( "2*(x+2x-4)=70
\n" ); document.write( "/2
\n" ); document.write( "3x-4=35
\n" ); document.write( "+4
\n" ); document.write( "3x=39
\n" ); document.write( "/3
\n" ); document.write( "x=13 the width
\n" ); document.write( "length = 2x-4===>2*13-4=22\r
\n" ); document.write( "\n" ); document.write( "m.ananth@hotmail.ca
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