document.write( "Question 399354: The perimeter of a rectangle is 70 cm. The length of the rectangle is 4 cm less than double the width. Find the length and width of the rectangle \n" ); document.write( "
Algebra.Com's Answer #282783 by mananth(16946) You can put this solution on YOUR website! let width =x \n" ); document.write( "length = 2x-4 \n" ); document.write( "perimeter = 70 \n" ); document.write( ".. \n" ); document.write( "2*(L+W)=perimeter \n" ); document.write( "2*(x+2x-4)=70 \n" ); document.write( "/2 \n" ); document.write( "3x-4=35 \n" ); document.write( "+4 \n" ); document.write( "3x=39 \n" ); document.write( "/3 \n" ); document.write( "x=13 the width \n" ); document.write( "length = 2x-4===>2*13-4=22\r \n" ); document.write( "\n" ); document.write( "m.ananth@hotmail.ca \n" ); document.write( " |