document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=399250>Question 399250</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Determining an Equation of a line;  Functions defined by tables and graphs.  Write an equation in standard form of the line that has given slope and passes through the given point. \r<BR>\n" );
document.write( "\n" );
document.write( "m=- 3/2 : (4, 2) \r<BR>\n" );
document.write( "\n" );
document.write( "It has been 20 years since I have done Algebra and my son wants me to correct his work.  I have no book to reference for example questions to refresh my memory. (he forgot it.) Any assistance you can provide to get me going in the right direction would be greatly appreciated!!  :-)  Thank you.    </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #282732 by </B><A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><B>ankor@dixie-net.com(22740)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ankor@dixie-net.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=282732\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Write an equation in standard form of the line that has given slope and passes through the given point.<BR>\n" );
document.write( "m=- 3/2 : (4, 2) <BR>\n" );
document.write( ":<BR>\n" );
document.write( "Use the point/slope form: y - y1 = m(x - x1)<BR>\n" );
document.write( "In this problem m =-3/2; x1=4; y1=2<BR>\n" );
document.write( ":<BR>\n" );
document.write( "y - 2 = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=-3%2F2 ALIGN=MIDDLE  ALT=\"-3%2F2\"   DISABLED_style= \"max-width:90%; height:auto;\" >(x - 4)<BR>\n" );
document.write( "y - 2 = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=-3%2F2 ALIGN=MIDDLE  ALT=\"-3%2F2\"   DISABLED_style= \"max-width:90%; height:auto;\" >x - <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=-3%2F2 ALIGN=MIDDLE  ALT=\"-3%2F2\"   DISABLED_style= \"max-width:90%; height:auto;\" >(4)<BR>\n" );
document.write( "y - 2 = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=-3%2F2 ALIGN=MIDDLE  ALT=\"-3%2F2\"   DISABLED_style= \"max-width:90%; height:auto;\" >x + 6<BR>\n" );
document.write( "y = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=-3%2F2 ALIGN=MIDDLE  ALT=\"-3%2F2\"   DISABLED_style= \"max-width:90%; height:auto;\" >x + 6 + 2<BR>\n" );
document.write( "y = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=-3%2F2 ALIGN=MIDDLE  ALT=\"-3%2F2\"   DISABLED_style= \"max-width:90%; height:auto;\" >x + 8<BR>\n" );
document.write( "Convert to standard (ax + by = c) form; multiply by 2 to get rid of the fraction<BR>\n" );
document.write( "2y = -3x + 16<BR>\n" );
document.write( "3x + 2y = 16 is the standard form<BR>\n" );
document.write( ":<BR>\n" );
document.write( "You can check the equation: substitute the given points, 4 for x, and 2 for y, <BR>\n" );
document.write( "3(4) + 2(2) = 16\r<BR>\n" );
document.write( "\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );