document.write( "Question 399228: Michael has $12,500 to invest. He invests part in an account which earns 4.2% annual interest and the rest in an account which earns 6.2% annual interest. He earns $669.50 in interest at the end of the year. How much was invested at each rate? \n" ); document.write( "
Algebra.Com's Answer #282718 by robertb(5830)![]() ![]() You can put this solution on YOUR website! 0.042x + 0.062(12,500 - x) = 669.50 \n" ); document.write( "==> 0.042x + 775 - 0.062x = 669.50 \n" ); document.write( "==> -0.02x = -105.5 \n" ); document.write( "==> x = $5,275, the amount invested in 4.2% \n" ); document.write( "and 12,500 - x = $7,225, the amount invested in 6.2%. \n" ); document.write( " |