document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=43240>Question 43240</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 1/R= 1/R1 + 1/R2  SOLVE THE EQUATION FOR R1 IN TERMS OF R AND R2.\r<BR>\n" );
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document.write( "i KNOW the first step is to isolate 1/r1\r<BR>\n" );
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document.write( "1/r-1/r2=1/r1 \r<BR>\n" );
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document.write( "my guess is r1=  (r-r2)/r*r2 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #28269 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=28269\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Actually the best first step is to clear all fractions by multiplying by the lowest common denominator...here that is r*r1*r2...so we get<BR>\n" );
document.write( "1/r = 1/r1 + 1/r2<BR>\n" );
document.write( "r*r1*r2[1/r = 1/r1 + 1/r2]<BR>\n" );
document.write( "r1*r2 = r*r2 + r*r1   then collect terms with r1 and solve<BR>\n" );
document.write( "r1*r2 - r*r1 = r*r2<BR>\n" );
document.write( "r1(r2 - r) = r*r2 and finally<BR>\n" );
document.write( "r1 = r*r2 / (r2 - r) </SPAN>\n" );
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