document.write( "Question 399184: 1-in how many ways can a committee of 3 be selected from a class of 8 students? \r
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Algebra.Com's Answer #282689 by solver91311(24713)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( "It depends. Is it a committee of 3 equals, such that a committee consisting of Alice, Bill, and Julia is exactly the same as Julia, Alice, and Bill? Or is the order in which the people are specified significant?\r
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\n" ); document.write( "\n" ); document.write( "If it is the first way (order doesn't matter) then you need the number of combinations of 8 things taken 3 at a time.\r
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\n" ); document.write( "\n" ); document.write( "The number of combinations of things taken at a time, , is calculated by \r
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\n" ); document.write( "\n" ); document.write( "On the other hand, if order matters, then you need the number of permutations of 8 things taken 3 at a time. The calculation is very similar except that you remove one factor from the denominator, namely the number of ways you can arrange things. Hence: \r
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\n" ); document.write( "My calculator said it, I believe it, that settles it
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