document.write( "Question 399110: My son need help with his math homework,we have tried to work it since he been home from school the problem is;\r
\n" ); document.write( "\n" ); document.write( "Dennis mowed his next door neighbor's lawn for a handful of dimes and nickels, 80 coins in all. Upon completing the job he countesd out the coins and it came to to $6.60. how many of each coin did he earn? \r
\n" ); document.write( "\n" ); document.write( "Have to use a linear system to solve
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Algebra.Com's Answer #282645 by ankor@dixie-net.com(22740)\"\" \"About 
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Dennis mowed his next door neighbor's lawn for a handful of dimes and nickels, 80 coins in all.
\n" ); document.write( "Upon completing the job he counted out the coins and it came to to $6.60.
\n" ); document.write( " how many of each coin did he earn?
\n" ); document.write( ":
\n" ); document.write( "Let n = no. of nickels; let d = no. of dimes
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\n" ); document.write( "The no. of coins equation:
\n" ); document.write( "n + d = 80
\n" ); document.write( "or
\n" ); document.write( "n = (80-d), use this for substitution in the value equation
\n" ); document.write( ":
\n" ); document.write( "The total value equation
\n" ); document.write( ".05n + .10d = 6.60
\n" ); document.write( "Replace n with (80-d)
\n" ); document.write( ".05(80-d) + .10d = 6.60
\n" ); document.write( "4 - .05d + .10d = 6.60
\n" ); document.write( "-.05d + .10d = 6.60 - 4
\n" ); document.write( ".05d = 2.60
\n" ); document.write( "d = 2.6/.05
\n" ); document.write( "d = 52 dimes
\n" ); document.write( "then
\n" ); document.write( "80 - 52 = 28 nickels
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\n" ); document.write( "See if that come out right
\n" ); document.write( ".05(28) + .10(52) =
\n" ); document.write( "1.40 + 5.20 = 6.60 confirms our solution of 28 nickels and 52 dimes
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