document.write( "Question 399070: –|2x – 1| ≥ -3 im lost and confused about the first negative in front of the absolute and was wondering if some one can walk me threw it i do not want the answer just help on finding it \n" ); document.write( "

Algebra.Com's Answer #282631 by Tatiana_Stebko(1539) $\"\"$ $\"About$

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–|2x–1|≥-3 divide both sides by -1
\n" ); document.write( " if you divide the inequality by a negative number, its sign (≥) is changed to the opposite (≤)
\n" ); document.write( "|2x–1|≤3
\n" ); document.write( "-3≤(2x–1)≤3
\n" ); document.write( "-3+1≤2x≤3+1
\n" ); document.write( "-2≤2x≤4 divide by 2 (positive number)
\n" ); document.write( "-1≤x≤2
\n" ); document.write( "Answer -1≤x≤2 \n" ); document.write( "

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