document.write( "Question 398861: The cost of admission to the carnival was $50 for a group of 9 children and 2 adults. The admission was $61 for another group of 10 children and 3 adults. What was the admission for one child? For one adult?
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Algebra.Com's Answer #282524 by checkley79(3341)\"\" \"About 
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9C+2A=50 MULTIPLY THIS EQUATION BY 3
\n" ); document.write( "10C+3A=61 MULTIPLY THIS EQUATUION BY -2 & ADD.\r
\n" ); document.write( "\n" ); document.write( "27C+6A=150
\n" ); document.write( "-20C-6A=-122
\n" ); document.write( "--------------
\n" ); document.write( "7C=28
\n" ); document.write( "C=28/7
\n" ); document.write( "C=$4 PER CHILD.
\n" ); document.write( "9*4+2A=50
\n" ); document.write( "36+2A=50
\n" ); document.write( "2A=50-36
\n" ); document.write( "2A=14
\n" ); document.write( "A=14/2
\n" ); document.write( "A=$7 FOR ADULT.
\n" ); document.write( "PROOF:
\n" ); document.write( "10*4=3*7=61
\n" ); document.write( "40+21=61
\n" ); document.write( "61=61
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