document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=43230>Question 43230</A>This question is from textbook <A HREF=http://www.amazon.com/exec/obidos/ASIN/0534494498/algebrahomeworkh>algebra and trigonometry with analytic geometry</A><BR>\n" );
document.write( ": <I><SPAN STYLE=\"word-break: break-all;\"> Give the equation for the right half of the circle. C(2,3).  I plotted it out to x=2+squrt9-(y-3)^2.  Not sure about the signs if I have them right or not.  thanks for checking.<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #28250 by </B><A HREF=/tutors/aboutme.mpl?userid=psbhowmick><B>psbhowmick(878)</B></A><img src=\"/images/stars/stars-11.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=psbhowmick><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=psbhowmick><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=28250\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> You haven't specified the radius yet.<BR>\n" );
document.write( "But, I think (looking at the algebraic expression you wrote) the radius is 3.<BR>\n" );
document.write( "Then the equation of the circle with centre at (2,3) and radius equal to 3 units is<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%28x-2%29%5E2+%2B+%28y-3%29%5E2+=+3%5E2 ALIGN=MIDDLE  ALT=\"%28x-2%29%5E2+%2B+%28y-3%29%5E2+=+3%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" >_________(1)\r<BR>\n" );
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document.write( "As the equation of semi-circle which is the right half of the circle is reqd. so <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x+%3E=+2 ALIGN=MIDDLE  ALT=\"x+%3E=+2\"   DISABLED_style= \"max-width:90%; height:auto;\" >. <BR>\n" );
document.write( "Simplifying (1) we have<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%28x-2%29%5E2+=+3%5E2+-+%28y-3%29%5E2 ALIGN=MIDDLE  ALT=\"%28x-2%29%5E2+=+3%5E2+-+%28y-3%29%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "or <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%28x-2%29%5E2+=+9+-+%28y%5E2+-+6y+%2B+9%29 ALIGN=MIDDLE  ALT=\"%28x-2%29%5E2+=+9+-+%28y%5E2+-+6y+%2B+9%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "or <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%28x-2%29%5E2+=+9+-+y%5E2+%2B+6y+-+9 ALIGN=MIDDLE  ALT=\"%28x-2%29%5E2+=+9+-+y%5E2+%2B+6y+-+9\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "or <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%28x-2%29%5E2+=+6y+-+y%5E2 ALIGN=MIDDLE  ALT=\"%28x-2%29%5E2+=+6y+-+y%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "or <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x+=+2+%2B-+sqrt%28+6y+-+y%5E2+%29 ALIGN=MIDDLE  ALT=\"x+=+2+%2B-+sqrt%28+6y+-+y%5E2+%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > [square-rooting both sides and then adding 2 to both sides]\r<BR>\n" );
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document.write( "As 'x' has to be greater than or equal to 2, so <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x+=+2+%2B+sqrt%28+6y+-+y%5E2+%29 ALIGN=MIDDLE  ALT=\"x+=+2+%2B+sqrt%28+6y+-+y%5E2+%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > is the reqd equation to right half of the circle. </SPAN>\n" );
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