document.write( "Question 398796: one of the zeros of the function f(x)=x^3+5x^2-9x-45 is x=-5, find the zeros of the function \n" ); document.write( "

Algebra.Com's Answer #282484 by lwsshak3(11628) $\"\"$ $\"About$

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one of the zeros of the function f(x)=x^3+5x^2-9x-45 is x=-5, find the zeros of the function\r
\n" ); document.write( "\n" ); document.write( "To find the other zeros or roots of the given third degree equation,
\n" ); document.write( "divide the given equation by x+5 by long division method or if you know how to do synthetic division, use -5 as the root. \r
\n" ); document.write( "\n" ); document.write( "With this format I am working with, I cannot show you how to do this, but if you do it correctly, you will get a reduced second degree equation, x^2-9, which is a difference of two squares.\r
\n" ); document.write( "\n" ); document.write( "In factored form f(x) = (x+5)(x^2-9)=(x+5)(x+3)(x-3)
\n" ); document.write( "The zeros or roots of f(x)are:-5,-3,and 3\r
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