document.write( "Question 398764: what quantity x of a 65% acid solution must mix with a 20% solution to produce 300 mL of a 45% solution \n" ); document.write( "
Algebra.Com's Answer #282461 by nerdybill(7384)![]() ![]() You can put this solution on YOUR website! what quantity x of a 65% acid solution must mix with a 20% solution to produce 300 mL of a 45% solution \n" ); document.write( ". \n" ); document.write( "Let x = amount (mL) of 65% solution \n" ); document.write( "then \n" ); document.write( "300-x = amount (mL) of 20% solution \n" ); document.write( ". \n" ); document.write( ".65x + .20(300-x) = .45(300) \n" ); document.write( ".65x + 60-.20x = 135 \n" ); document.write( ".45x + 60 = 135 \n" ); document.write( ".45x = 75 \n" ); document.write( "x = 166.67 mL (65% solution) \n" ); document.write( ". \n" ); document.write( "amount of 20% solution: \n" ); document.write( "300-x = 300-166.67 = 133.33 mL \n" ); document.write( " \n" ); document.write( " |