document.write( "Question 398764: what quantity x of a 65% acid solution must mix with a 20% solution to produce 300 mL of a 45% solution \n" ); document.write( "
Algebra.Com's Answer #282461 by nerdybill(7384)\"\" \"About 
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what quantity x of a 65% acid solution must mix with a 20% solution to produce 300 mL of a 45% solution
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\n" ); document.write( "Let x = amount (mL) of 65% solution
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\n" ); document.write( "300-x = amount (mL) of 20% solution
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\n" ); document.write( ".65x + .20(300-x) = .45(300)
\n" ); document.write( ".65x + 60-.20x = 135
\n" ); document.write( ".45x + 60 = 135
\n" ); document.write( ".45x = 75
\n" ); document.write( "x = 166.67 mL (65% solution)
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\n" ); document.write( "amount of 20% solution:
\n" ); document.write( "300-x = 300-166.67 = 133.33 mL
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