document.write( "Question 43220: A bus leaves a station at 1 p.m., traveling west at an average rate of 44 mi/h. One hour later a second bus leaves along the same route, traveling at 54 mi/h. At what time will the two buses be 274 mi apart? \n" ); document.write( "
Algebra.Com's Answer #28246 by aaaaaaaa(138) ![]() You can put this solution on YOUR website! The position of the first bus at x hours (counting from the time the second bus departed) is:\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The position of the second one is:\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "We want to solve for how many hours (x), the following equation will be true:\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Since we used \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "And we have a linear equation! Solving it we have:\r \n" ); document.write( "\n" ); document.write( "
\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Verifying...\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Therefore, that distance will happen at 31.8 hours after the second bus left (2 p.m or 14:00). Remember that 0.8 hours is |