document.write( "Question 398582: Find all solutions of the simultaneous equations\r
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document.write( "2x^2=14+yz
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document.write( "2y^2=14+zx
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document.write( "2z^2=14+xy\r
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document.write( "I tried everything but i seen to go in a circle I came up to notice that there is pattern meaning that each variable changes position hence it could mean that x=z=y.. but im not sure at all.. \r
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document.write( "help please
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Algebra.Com's Answer #282396 by richard1234(7193)![]() ![]() You can put this solution on YOUR website! It is symmetric, but doesn't necessarily mean that x = y = z (we could prove that it's true if it is).\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Without loss of generality, suppose \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Taking subsets of the inequality, we get \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "If we assume all x,y,z are negative, then by the same logic we get the ordered triple ( \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "However, what happens if some of the numbers are positive and others are negative? In this case we can assume \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Suppose we subtract the first equation from the second to obtain\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "x is positive, and since y has a magnitude larger than x, y is also positive. However this would not satisfy the inequality \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "x is negative, and since y has a larger magnitude and x-y is less than zero, then y is positive. However this would not satisfy \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The only possibility is if \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Subtracting the first equation from the second equation,\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "These two equations cannot be satisfied, since it implies \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Thus, the only solutions are when x = y = z, or ( |