document.write( "Question 398582: Find all solutions of the simultaneous equations\r
\n" ); document.write( "\n" ); document.write( "2x^2=14+yz
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\n" ); document.write( "\n" ); document.write( "I tried everything but i seen to go in a circle I came up to notice that there is pattern meaning that each variable changes position hence it could mean that x=z=y.. but im not sure at all.. \r
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Algebra.Com's Answer #282396 by richard1234(7193)\"\" \"About 
You can put this solution on YOUR website!
It is symmetric, but doesn't necessarily mean that x = y = z (we could prove that it's true if it is).\r
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\n" ); document.write( "\n" ); document.write( "Without loss of generality, suppose \"0+%3C=+x+%3C=+y+%3C=+z\" (we can make such an assumption because it's symmetric, but we must also consider negative solutions, if they exist). Then,\r
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\n" ); document.write( "\n" ); document.write( "\"2z%5E2+%3E=+2y%5E2+%3E=+2x%5E2\"\r
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\n" ); document.write( "\n" ); document.write( "\"14+%2B+xy+%3E=+14+%2B+xz+%3E=+14+%2B+yz\" --> \"xy+%3E=+xz+%3E=+yz\" (using substitution)\r
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\n" ); document.write( "\n" ); document.write( "Taking subsets of the inequality, we get \"xy+%3E=+xz\", \"xy+%3E=+yz\", \"xz+%3E=+yz\", which implies \"y+%3E=+z\", \"x+%3E=+z\", \"x+%3E=+y\". Since we already have \"z+%3E=+y\", \"z+%3E=+x\", \"y+%3E=+x\" from our first assumption, this implies \"x+=+y+=+z\". Setting all variables equal to x, we get \"2x%5E2+=+14+%2B+x%5E2\", \"x+=+sqrt%2814%29\", so (\"sqrt%2814%29\", \"sqrt%2814%29\", \"sqrt%2814%29\") is a solution.\r
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\n" ); document.write( "\n" ); document.write( "If we assume all x,y,z are negative, then by the same logic we get the ordered triple (\"-sqrt%2814%29\", \"-sqrt%2814%29\", \"-sqrt%2814%29\") as another solution.\r
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\n" ); document.write( "\n" ); document.write( "However, what happens if some of the numbers are positive and others are negative? In this case we can assume \"0+%3C+abs%28x%29+%3C=+abs%28y%29+%3C=+abs%28z%29\". Since the magnitudes of the squares of the numbers are still in order, we get \"2z%5E2+%3E=+2y%5E2+%3E=+2x%5E2\", and the inequalities \"y+%3E=+z\", \"x+%3E=+z\", and \"x+%3E=+y\" similar to above. Now, suppose we assume that z is positive. If this is the case, x and y are both positive, and their magnitudes are larger, thus contradiction, so z is negative.\r
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\n" ); document.write( "\n" ); document.write( "Suppose we subtract the first equation from the second to obtain\r
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\n" ); document.write( "\n" ); document.write( "\"2y%5E2+-+2x%5E2+=+zx+-+yz+=+z%28x-y%29\". The left side is positive since the magnitude of y is larger than the magnitude of x. Since z is negative, it follows that x-y is also negative. This implies either:\r
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\n" ); document.write( "\n" ); document.write( "x is positive, and since y has a magnitude larger than x, y is also positive. However this would not satisfy the inequality \"x+%3E=+y\" (unless x = y).\r
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\n" ); document.write( "\n" ); document.write( "x is negative, and since y has a larger magnitude and x-y is less than zero, then y is positive. However this would not satisfy \"x+%3E=+y\" in any case (since none of the variables can be zero).\r
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\n" ); document.write( "\n" ); document.write( "The only possibility is if \"x+=+y\" and \"z+%3C+0\". If we replace y with x we get the system:\r
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\n" ); document.write( "\n" ); document.write( "\"2x%5E2+=+14+%2B+xz\"
\n" ); document.write( "\"2z%5E2+=+14+%2B+x%5E2\"\r
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\n" ); document.write( "\n" ); document.write( "Subtracting the first equation from the second equation,\r
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\n" ); document.write( "\n" ); document.write( "\"2z%5E2+-+2x%5E2+=+x%5E2+-+xz+=+x%28x+-+z%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"2%28z-x%29%28z%2Bx%29+=+x%28x-z%29\" Cancel z-x\r
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\n" ); document.write( "\n" ); document.write( "\"2%28z-x%29+=+-x\"\r
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\n" ); document.write( "\n" ); document.write( "\"2z+-+2x+=+-x\" --> \"2z+=+x\" --> \"z+=+x%2F2\". Therefore we can replace y with x, z with x/2 in the first and third equations to obtain:\r
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\n" ); document.write( "\n" ); document.write( "\"2x%5E2+=+14+%2B+x%28x%2F2%29\" --> \"%283%2F4%29x%5E2+=+14\"
\n" ); document.write( "\"2%28x%2F2%29%5E2+=+14+%2B+x%5E2\" --> \"%28-1%2F2%29x%5E2+=+14\"\r
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\n" ); document.write( "\n" ); document.write( "These two equations cannot be satisfied, since it implies \"3%2F4+=+-1%2F2\" (note that x cannot be zero, it can be proven using contradiction that none of x,y,z can equal zero). Therefore there are no solutions in this case.\r
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\n" ); document.write( "\n" ); document.write( "Thus, the only solutions are when x = y = z, or (\"sqrt%2814%29\", \"sqrt%2814%29\", \"sqrt%2814%29\") and (\"-sqrt%2814%29\", \"-sqrt%2814%29\", \"-sqrt%2814%29\").
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