document.write( "Question 43205This question is from textbook Beginning Algebra
\n" ); document.write( ": The length of a rectangle is 2 cm more than 3 times its width. If the area of the rectangle is 83 cm^2, find the dimensions of the rectangle to the nearest thousandth.\r
\n" ); document.write( "\n" ); document.write( "Ive tried a million times to get this and I'm stumped....
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Algebra.Com's Answer #28238 by Nate(3500)\"\" \"About 
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width = w
\n" ); document.write( "length = 3w + 2
\n" ); document.write( "\"lw+=+area\"
\n" ); document.write( "\"%283w+%2B+2%29w+=+83\"
\n" ); document.write( "\"3w%5E2+%2B+2w+-+83+=+0\"
\n" ); document.write( "\"w+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+\"
\n" ); document.write( "\"w+=+%28-2+%2B-+sqrt%28+2%5E2-4%2A3%2A%28-83%29+%29%29%2F%282%2A3%29+\"
\n" ); document.write( "\"w+=+%28-2+%2B-+sqrt%28+1000+%29%29%2F%286%29+\"
\n" ); document.write( "\"w+=+-1%2F3+%2B+sqrt%282%2A5%2A2%2A5%2A2%2A5%29%2F6\"
\n" ); document.write( "\"w+=+-1%2F3+%2B+10sqrt%2810%29%2F6\" about 4.9371
\n" ); document.write( "PLUG:
\n" ); document.write( "length = 3w + 2 = length = 3(-1/3 + 10sqrt(10)/6) + 2 = 1 + 5sqrt(10)
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