document.write( "Question 398541: Maria bicycles 6km an hour faster than Praedup. In the same time it takes Praedup to bicycle 42km, Maria can bicycle 60km. How fast does each bicyclist travel? \n" ); document.write( "
Algebra.Com's Answer #282364 by checkley79(3341)\"\" \"About 
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D=RT
\n" ); document.write( "60=(X+6)T MARIA'S RIDE
\n" ); document.write( "T=60/(X+6)
\n" ); document.write( "42=XT PRARDUP'S RIDE
\n" ); document.write( "T=42/X
\n" ); document.write( "60/(X+6)=42/X
\n" ); document.write( "42(X+6)=60X
\n" ); document.write( "42X+262=60X
\n" ); document.write( "42X-60X=-262
\n" ); document.write( "-18X=-262
\n" ); document.write( "X=-262/-18
\n" ); document.write( "X=14 KPH FOR PRAEUR'S SPEED.
\n" ); document.write( "14+6=20 KPH FOR MARIA'S SPEED.
\n" ); document.write( "PROOF:
\n" ); document.write( "60/20=42/14
\n" ); document.write( "3=3
\n" ); document.write( "
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