document.write( "Question 398541: Maria bicycles 6km an hour faster than Praedup. In the same time it takes Praedup to bicycle 42km, Maria can bicycle 60km. How fast does each bicyclist travel? \n" ); document.write( "
Algebra.Com's Answer #282364 by checkley79(3341)![]() ![]() ![]() You can put this solution on YOUR website! D=RT \n" ); document.write( "60=(X+6)T MARIA'S RIDE \n" ); document.write( "T=60/(X+6) \n" ); document.write( "42=XT PRARDUP'S RIDE \n" ); document.write( "T=42/X \n" ); document.write( "60/(X+6)=42/X \n" ); document.write( "42(X+6)=60X \n" ); document.write( "42X+262=60X \n" ); document.write( "42X-60X=-262 \n" ); document.write( "-18X=-262 \n" ); document.write( "X=-262/-18 \n" ); document.write( "X=14 KPH FOR PRAEUR'S SPEED. \n" ); document.write( "14+6=20 KPH FOR MARIA'S SPEED. \n" ); document.write( "PROOF: \n" ); document.write( "60/20=42/14 \n" ); document.write( "3=3 \n" ); document.write( " |