document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=398552>Question 398552</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A rectangle is 12 cm longer than it is wide. Its perimeter is 100 cm. Find its length and width. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #282363 by </B><A HREF=/tutors/aboutme.mpl?userid=richard1234><B>richard1234(7193)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richard1234><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richard1234><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=282363\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let the width be w and the length 12+w. Then,\r<BR>\n" );
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document.write( "2(w + (12+w)) = 100\r<BR>\n" );
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document.write( "w + (12+w) = 50\r<BR>\n" );
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document.write( "2w + 12 = 50 --> w = 19, so the width is 19 and the length is 31. </SPAN>\n" );
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