document.write( "Question 398424: x+1/4 = 1/6 + 2-x/3 \n" ); document.write( "
Algebra.Com's Answer #282330 by unlockmath(1688)![]() ![]() You can put this solution on YOUR website! Hello, \n" ); document.write( "Let's get rid of the fractions x+1/4 = 1/6 + 2-x/3 by multiply this by 12 to get (Note: I'm assuming x & 2 are by themselves and not part of the numerator): \n" ); document.write( "12x + 3 = 2 + 24 - 4x \n" ); document.write( "Add 4x and subtract 3 from both sides: \n" ); document.write( "16x=23 \n" ); document.write( "Divide by 16 to get: \n" ); document.write( "x=23/16\r \n" ); document.write( "\n" ); document.write( "(if they are part of the numerator then we do this:) \n" ); document.write( "Multiply by 12: \n" ); document.write( "3(x+1) = 2 + 4(2-x) \n" ); document.write( "Rewritten as: \n" ); document.write( "3x+3=2+8-4x \n" ); document.write( "Add 4x and subtract 3 to get: \n" ); document.write( "7x=7 \n" ); document.write( "x=1 \n" ); document.write( "Make sense? \n" ); document.write( "RJ \n" ); document.write( "www.math-unlock.com \n" ); document.write( " |