document.write( "Question 398415: I think i may be on the right track but not sure. Here is the problem: One hose can fill a pool in 20 hours. Another hose can fill the pool in 16 hours. How long would it take the two hoses, working together to fill the pool?
\n" ); document.write( "Here is how i set it up t/20 + t/16 with a LCD of 2. 2 x (t/20 + t/16) = 2 x 1. I reduced it down to 10t+8t=2, I combine my like terms this gives me 18t=2. Now do i divide 18 into 2 or 2 into 18? Am I on the right track to solving this problem? \n" ); document.write( "

Algebra.Com's Answer #282328 by stanbon(75887) $\"\"$ $\"About$

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I think i may be on the right track but not sure. Here is the problem: One hose can fill a pool in 20 hours. Another hose can fill the pool in 16 hours. How long would it take the two hoses, working together to fill the pool?
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\n" ); document.write( "Equation:
\n" ); document.write( "rate + rate = together rate
\n" ); document.write( "1/20 + 1/16 = 1/t
\n" ); document.write( "Multiply thru by 80t to get:
\n" ); document.write( "4t + 5t = 80
\n" ); document.write( "9t = 80
\n" ); document.write( "time to fill the pool together is t = 80/9 hrs.
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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