document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=398294>Question 398294</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The class president prepared juice for the class. She prepared 5 liters of juice that was 3 parts pure juice and 7 parts water. This was too sweet. How many liters of water should she add so that the concentration is reduced to 25% and the sweetness is improved? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #282270 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=282270\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let x=amt of water to add to get a 25% concentration<BR>\n" );
document.write( "current concentration:<BR>\n" );
document.write( "liters of juice = .3*5 =1.5 liters<BR>\n" );
document.write( "liters of water = .7*5 =3.5 liters\r<BR>\n" );
document.write( "\n" );
document.write( "new 25% concentration:<BR>\n" );
document.write( "1.5/(1.5+3.5+x)=.25=1/4<BR>\n" );
document.write( "5+x=6<BR>\n" );
document.write( "x=1<BR>\n" );
document.write( "ans:1 liter of water must be added to reduce the concentration of juice to 25%  </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );