document.write( "Question 398290: Tom's boat will go 15 miles per
\n" ); document.write( "hour in still water. If he can go 12 miles downstream in the
\n" ); document.write( "same amount of time as it takes to go 9 miles upstream,
\n" ); document.write( "then what is the speed of the current?\r
\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "
Algebra.Com's Answer #282269 by mananth(16946)\"\" \"About 
You can put this solution on YOUR website!
Tom's boat will go 15 miles per
\n" ); document.write( "hour in still water. If he can go 12 miles downstream in the
\n" ); document.write( "same amount of time as it takes to go 9 miles upstream,
\n" ); document.write( "then what is the speed of the current?\r
\n" ); document.write( "\n" ); document.write( "...\r
\n" ); document.write( "\n" ); document.write( "speed of current = x mph
\n" ); document.write( "boat speed = 15 mph
\n" ); document.write( "...
\n" ); document.write( "t = d/r
\n" ); document.write( "t upstream = t downstream
\n" ); document.write( "9/(15-x)= 12/(15+x)
\n" ); document.write( "9(15+x)=12(15-x)
\n" ); document.write( "/3
\n" ); document.write( "3(15+x)=4(15-x)
\n" ); document.write( "45+3x=60-4x
\n" ); document.write( "3x+4x=60-45
\n" ); document.write( "7x=15
\n" ); document.write( "/7
\n" ); document.write( "x= 2.14 mph current speed\r
\n" ); document.write( "\n" ); document.write( "...
\n" ); document.write( "m.ananth@hotmail.ca\r
\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "
\n" );