document.write( "Question 398296: Junior’s boat will go 15 miles per
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document.write( "hour in still water. If he can go 12 miles downstream in the
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document.write( "same amount of time as it takes to go 9 miles upstream,
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document.write( "then what is the speed of the current?
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Algebra.Com's Answer #282266 by mananth(16946)![]() ![]() You can put this solution on YOUR website! Junior’s boat will go 15 miles per \n" ); document.write( "hour in still water. If he can go 12 miles downstream in the \n" ); document.write( "same amount of time as it takes to go 9 miles upstream, \n" ); document.write( "then what is the speed of the current?\r \n" ); document.write( "\n" ); document.write( ".. \n" ); document.write( "speed of current = x mph \n" ); document.write( "boat speed = 15 mph \n" ); document.write( "... \n" ); document.write( "t = d/r \n" ); document.write( "t upstream = t downstream \n" ); document.write( "9/(15-x)= 12/(15+x) \n" ); document.write( "9(15+x)=12(15-x) \n" ); document.write( "/3 \n" ); document.write( "3(15+x)=4(15-x) \n" ); document.write( "45+3x=60-4x \n" ); document.write( "3x+4x=60-45 \n" ); document.write( "7x=15 \n" ); document.write( "/7 \n" ); document.write( "x= 2.14 mph current speed\r \n" ); document.write( "\n" ); document.write( "... \n" ); document.write( "m.ananth@hotmail.ca \n" ); document.write( " |