document.write( "Question 398141: After performing the test discussed in question #2 above, the p-value calculated to .062. Would you accept or reject the null based on this information? Explain your answer\r
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document.write( "Note: Here is question 2:
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document.write( "As the research, you believe that Sample A has a lower mean than Sample B and you are going to perform a t-test to determine if this is true at a 95% confidence level. State the numeric null and alternative hypothesis. \n" );
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Algebra.Com's Answer #282246 by robertb(5830)![]() ![]() You can put this solution on YOUR website! 1 - 0.95 = 0.05 < 0.062, so do NOT reject the null hypothesis. Or, Sample A does not have a lower mean than Sample B.\r \n" ); document.write( "\n" ); document.write( "From Question 2, \n" ); document.write( " \n" ); document.write( " |