document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=398264>Question 398264</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The length of the foundation of a rectangular house is to be 5 meters more than its width. Find the length of the house if the perimeter must be 70 meters. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #282244 by </B><A HREF=/tutors/aboutme.mpl?userid=richard1234><B>richard1234(7193)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richard1234><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richard1234><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=282244\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Suppose the width is W and the length is W+5. Then,\r<BR>\n" );
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document.write( "2(W + (W+5)) = 70\r<BR>\n" );
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document.write( "W + (W+5) = 35\r<BR>\n" );
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document.write( "2W + 5 = 35 --> W = 15, L = W+5 = 20 meters </SPAN>\n" );
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