document.write( "Question 398154: A part time construction worker earned $7300. He invested some money at 7 percent and the rest at 6 percent. If he received $458 total in interest at the end of the year, how much of his money was invested at 7 percent? \n" ); document.write( "
Algebra.Com's Answer #282217 by rfer(16322)![]() ![]() ![]() You can put this solution on YOUR website! 0.07x+0.06(7300-x)=458 \n" ); document.write( "0.07x+438-0.06x=458 \n" ); document.write( "0.01x=20 \n" ); document.write( "x=2000 at 7% \n" ); document.write( "7300-x=5300 at 6% \n" ); document.write( " |