document.write( "Question 398154: A part time construction worker earned $7300. He invested some money at 7 percent and the rest at 6 percent. If he received $458 total in interest at the end of the year, how much of his money was invested at 7 percent? \n" ); document.write( "
Algebra.Com's Answer #282217 by rfer(16322)\"\" \"About 
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0.07x+0.06(7300-x)=458
\n" ); document.write( "0.07x+438-0.06x=458
\n" ); document.write( "0.01x=20
\n" ); document.write( "x=2000 at 7%
\n" ); document.write( "7300-x=5300 at 6%
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