document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=398147>Question 398147</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Solve each system by substitution or addition, whichever is easier.\r<BR>\n" );
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document.write( "2y-3x=-1<BR>\n" );
document.write( "5y+3x=29<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #282215 by </B><A HREF=/tutors/aboutme.mpl?userid=richard1234><B>richard1234(7193)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richard1234><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richard1234><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=282215\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Addition's much easier. If we add the two equations, we get\r<BR>\n" );
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document.write( "(2y - 3x) + (5y + 3x) = 28\r<BR>\n" );
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document.write( "7y = 28\r<BR>\n" );
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document.write( "y = 4. Replace y = 4 into either equation to get x = 3. </SPAN>\n" );
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