Given that
is a rational number, what can you say about the value of n?
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document.write( "Only integer powers of 10 are rational. So the exponent\r\n" );
document.write( "must be an integer, say k\r\n" );
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document.write( "n-1 = 2k\r\n" );
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document.write( "n = 2k+1\r\n" );
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document.write( "Therefore n must be odd in order that
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document.write( "be rational.\r\n" );
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document.write( "What if both
and
are rational? What can you say about the value of n?
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document.write( "For\r\n" );
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document.write( "Only integer powers of 10 are rational. So the exponent\r\n" );
document.write( "must be an integer, say p\r\n" );
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document.write( "n-1 = 3p\r\n" );
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document.write( "n = 3p+1\r\n" );
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document.write( "Therefore n must be 1 more than a multiple of 3\r\n" );
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document.write( "Now we set the exponents equal:\r\n" );
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document.write( "n = 3p+1 = 2k+1\r\n" );
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document.write( "3p = 2k\r\n" );
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document.write( "2p+p = 2k\r\n" );
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document.write( "p +
= 2k\r\n" );
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document.write( "
= 2k-p\r\n" );
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document.write( "The right side is an integer, so the left side must be also\r\n" );
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document.write( "Let that integer be A\r\n" );
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document.write( "Then \r\n" );
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document.write( "
= A \r\n" );
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document.write( "p = 2A\r\n" );
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document.write( "Substitute in\r\n" );
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document.write( "3p = 2k\r\n" );
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document.write( "3(2A) = 2k\r\n" );
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document.write( "6A = 2k\r\n" );
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document.write( "3A = k\r\n" );
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document.write( "Now supstitute in\r\n" );
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document.write( "n = 3p+1 = 2k+1\r\n" );
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document.write( "n = 3(2A)+1 = 2(3A)+1\r\n" );
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document.write( "n = 6A+1 = 6A+1 \r\n" );
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document.write( "So n must be 1 more than a multiple of 6.\r\n" );
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document.write( "Edwin
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