document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=398238>Question 398238</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the equation of the line through (6,-3) which meets the x axis at x=3. Enter your solution in the form y=mx+b. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #282199 by </B><A HREF=/tutors/aboutme.mpl?userid=nerdybill><B>nerdybill(7384)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=nerdybill><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=nerdybill><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=282199\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Find the equation of the line through (6,-3) which meets the x axis at x=3. Enter your solution in the form y=mx+b.<BR>\n" );
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document.write( "If a line \"meets the x axis at x=3\" then the point must be at (3,0)<BR>\n" );
document.write( "Two points given then: (3,0) and (6,-3)<BR>\n" );
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document.write( "Slope = (y2-y1)/(x2-x1) = (-3-0)/(6-3) = -3/3 = -1<BR>\n" );
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document.write( "plug (3,0) and -1 into \"point-slope\" form:<BR>\n" );
document.write( "y - y1 = m(x - x1)<BR>\n" );
document.write( "y - 0 = -1(x - 3)<BR>\n" );
document.write( "y = -1(x - 3)<BR>\n" );
document.write( "y = -x + 3 (this is what they're looking for)<BR>\n" );
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