document.write( "Question 398220: Ive totally lost myself with this, so if there is anyone that can help please\r
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\n" ); document.write( "\n" ); document.write( "2log[4](x)+log[4](3)=log[4](x)-log[4](2)\r
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\n" ); document.write( "\n" ); document.write( "All the 4s are log base 4\r
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Algebra.Com's Answer #282175 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
2log[4](x)+log[4](3)=log[4](x)-log[4](2) \r
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\n" ); document.write( "log4(x^2) + log4(3) = log4[x/2]
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\n" ); document.write( "log4(3x^2) = log4(x/2)
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\n" ); document.write( "3x^2 = x/2
\n" ); document.write( "6x^2 = x
\n" ); document.write( "6x^2-x = 0
\n" ); document.write( "x(6x-1) = 0
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\n" ); document.write( "x cannot be zero, so x = 1/6 is the only answer.
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\n" ); document.write( "Let me know if you do not understand all this.
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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