document.write( "Question 398210: I am being confused with the formula for figuring out the distance and time in this problem. Please help me with this.\r
\n" ); document.write( "\n" ); document.write( "Aya rode her bicycle from her house to a friend's house, averaging 16 kilometers per hour. It turned dark before she was ready to return home, so her friend drove her home at a rate of 80 kilometers per hour. If Aya's total traveling time was three hours, how far away did her friend live?\r
\n" ); document.write( "\n" ); document.write( "Thank you for your time.
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Algebra.Com's Answer #282161 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
Aya rode her bicycle from her house to a friend's house, averaging 16 kilometers per hour. It turned dark before she was ready to return home, so her friend drove her home at a rate of 80 kilometers per hour. If Aya's total traveling time was three hours, how far away did her friend live?
\n" ); document.write( "------
\n" ); document.write( "To DATA:
\n" ); document.write( "rate = 16 km/hr ; distance = x km ; time = d/r = x/16 hrs
\n" ); document.write( "----------------
\n" ); document.write( "From DATA:
\n" ); document.write( "rate = 80 km/hr ; distance = x km ; time = d/r = x/80 hrs
\n" ); document.write( "-----------------
\n" ); document.write( "Equation:
\n" ); document.write( "time + time = 3 hrs
\n" ); document.write( "---
\n" ); document.write( "x/16 + x/80 = 3
\n" ); document.write( "----
\n" ); document.write( "Multiply thru by 80 to get:
\n" ); document.write( "5x + x = 240
\n" ); document.write( "6x = 240
\n" ); document.write( "x = 40 km (distance to her friend's house).
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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