document.write( "Question 398210: I am being confused with the formula for figuring out the distance and time in this problem. Please help me with this.\r
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document.write( "Aya rode her bicycle from her house to a friend's house, averaging 16 kilometers per hour. It turned dark before she was ready to return home, so her friend drove her home at a rate of 80 kilometers per hour. If Aya's total traveling time was three hours, how far away did her friend live?\r
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document.write( "Thank you for your time. \n" );
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Algebra.Com's Answer #282161 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! Aya rode her bicycle from her house to a friend's house, averaging 16 kilometers per hour. It turned dark before she was ready to return home, so her friend drove her home at a rate of 80 kilometers per hour. If Aya's total traveling time was three hours, how far away did her friend live? \n" ); document.write( "------ \n" ); document.write( "To DATA: \n" ); document.write( "rate = 16 km/hr ; distance = x km ; time = d/r = x/16 hrs \n" ); document.write( "---------------- \n" ); document.write( "From DATA: \n" ); document.write( "rate = 80 km/hr ; distance = x km ; time = d/r = x/80 hrs \n" ); document.write( "----------------- \n" ); document.write( "Equation: \n" ); document.write( "time + time = 3 hrs \n" ); document.write( "--- \n" ); document.write( "x/16 + x/80 = 3 \n" ); document.write( "---- \n" ); document.write( "Multiply thru by 80 to get: \n" ); document.write( "5x + x = 240 \n" ); document.write( "6x = 240 \n" ); document.write( "x = 40 km (distance to her friend's house). \n" ); document.write( "============================================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |