document.write( "Question 398200: What quantity x of a 65% acid solution must be mixed with a 20% solution to produce 300 mL of a 45% solution.
\n" ); document.write( "Amount x=_____
\n" ); document.write( "I set up a system of two equations:
\n" ); document.write( "x+y=300
\n" ); document.write( ".65x+.20y=.45
\n" ); document.write( "I solved for x and got 133.33. What am I doing wrong?
\n" ); document.write( "Thank you!!
\n" ); document.write( " \n" ); document.write( "

Algebra.Com's Answer #282138 by ewatrrr(24785) $\"\"$ $\"About$

You can put this solution on YOUR website!


\n" );
document.write( "Hi
\n" );
document.write( "Let x and (300-x)represent the amounts of 65% and 20% solutions respectively
\n" );
document.write( "Question states***
\n" );
document.write( "Mixing together to form 300ml of 45% solution
\n" );
document.write( "  .65x + .20(300-x) = .45*300ml
\n" );
document.write( "solving for x
\n" );
document.write( "          .45x = .25*300ml
\n" );
document.write( "             x = .25*300ml/.45
\n" );
document.write( "             x = 166.6667ml of 65% solution \n" );
document.write( "

\n" );