document.write( "Question 398200: What quantity x of a 65% acid solution must be mixed with a 20% solution to produce 300 mL of a 45% solution.
\n" ); document.write( "Amount x=_____
\n" ); document.write( "I set up a system of two equations:
\n" ); document.write( "x+y=300
\n" ); document.write( ".65x+.20y=.45
\n" ); document.write( "I solved for x and got 133.33. What am I doing wrong?
\n" ); document.write( "Thank you!!
\n" ); document.write( " \n" ); document.write( "

Algebra.Com's Answer #282137 by scott8148(6628) $\"\"$ $\"About$

You can put this solution on YOUR website!
you left the 300 ml out of the 2nd equation ___ .65x + .20y = .45(300) \n" ); document.write( "

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