document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=398200>Question 398200</A>: <I><SPAN STYLE=\"word-break: break-all;\"> What quantity x of a 65% acid solution must be mixed with a 20% solution to produce 300 mL of a 45% solution. <BR>\n" );
document.write( "Amount x=_____<BR>\n" );
document.write( "I set up a system of two equations:<BR>\n" );
document.write( "x+y=300<BR>\n" );
document.write( ".65x+.20y=.45<BR>\n" );
document.write( "I solved for x and got 133.33. What am I doing wrong?<BR>\n" );
document.write( "Thank you!!<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #282136 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=282136\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> What quantity x of a 65% acid solution must be mixed with a 20% solution to produce 300 mL of a 45% solution.<BR>\n" );
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document.write( "Equations: <BR>\n" );
document.write( "Quantity Eq:  x+y=300 mL<BR>\n" );
document.write( "Acid Eq::::: 0.65x+.20y=.45*300<BR>\n" );
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document.write( "Multiply thru the 1st by 65<BR>\n" );
document.write( "Multiply thru the 2nd by 100<BR>\n" );
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document.write( "65x + 65y = 65*300<BR>\n" );
document.write( "65x + 20y = 45*300<BR>\n" );
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document.write( "Subtract and solve for \"y\":<BR>\n" );
document.write( "45y = 20*300<BR>\n" );
document.write( "y = (4/9)300<BR>\n" );
document.write( "y = 133 1/3 mL (amt of 20% solution needed in the mixture)<BR>\n" );
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document.write( "Solve for \"x\":<BR>\n" );
document.write( "x+y = 300<BR>\n" );
document.write( "x = 300 - 133 1/3<BR>\n" );
document.write( "x = 166 3/4 mL (amt of 65% solution needed in the mixture)<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );