document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=398199>Question 398199</A>: <I><SPAN STYLE=\"word-break: break-all;\"> (2/9) to power of -2. Simplify the expression. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #282134 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=282134\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\">  (2/9) to power of -2. Simplify the expression.<BR>\n" );
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document.write( "The negative in the exponent tells you to invert.<BR>\n" );
document.write( "The 2 in the exponent tells you to square.<BR>\n" );
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document.write( "You may perform these instructions in any order.<BR>\n" );
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document.write( "(2/9)^(-2)<BR>\n" );
document.write( "If you invert 1st you get:<BR>\n" );
document.write( "(9/2)^2<BR>\n" );
document.write( "You then square to get:<BR>\n" );
document.write( "81/4<BR>\n" );
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document.write( "If you square 1st you get:<BR>\n" );
document.write( "(4/81)^(-1)<BR>\n" );
document.write( "You then invert to get:<BR>\n" );
document.write( "81/4<BR>\n" );
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document.write( "Notice, the answers are the same no <BR>\n" );
document.write( "matter what order you follow.<BR>\n" );
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document.write( "cheers,<BR>\n" );
document.write( "stan H. </SPAN>\n" );
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