document.write( "Question 398178: the perimeter of a rectangle is 68 inches. the length exceeds the width by 10 inches find the length and the width \n" ); document.write( "

Algebra.Com's Answer #282130 by ewatrrr(24785) $\"\"$ $\"About$

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document.write( "Hi
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document.write( "the length exceeds the width by 10 
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document.write( "Let x and (x+10in) represent the width and length respectively
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document.write( "Question states***  (Note:  P = 2L + 2W
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document.write( "  2x + 2(x+10in) = 68in
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document.write( "solving for x
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document.write( "   4x + 20in = 68in
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document.write( "      4x = 48in
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document.write( "       x = 12in, the width.  the length is 22in  (12in + 10in
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document.write( "CHECKING our Answer***
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document.write( "  2*12in + 2*22in = 68in \n" );
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