document.write( "Question 398132: Find three consecutive odd integers such that the sum of twice the first, twice the second, and three times the third is 9. An explanation would be great too! \n" ); document.write( "
Algebra.Com's Answer #282114 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
Find three consecutive odd integers such that the sum of twice the first, twice the second, and three times the third is 9.
\n" ); document.write( "---
\n" ); document.write( "Odd numbers must be represented as an odd # more than or less than
\n" ); document.write( "an even number.
\n" ); document.write( "-----
\n" ); document.write( "1st: 2x-1
\n" ); document.write( "2nd: 2x+1
\n" ); document.write( "3rd: 2x+3
\n" ); document.write( "---------------
\n" ); document.write( "Equation:
\n" ); document.write( "2(2x-1)+2(2x+1)+3(2x+3) = 9
\n" ); document.write( "4x-2+4x+2+6x+9 = 9
\n" ); document.write( "14x + 9 = 9
\n" ); document.write( "14x = 0
\n" ); document.write( "x = 0
\n" ); document.write( "---
\n" ); document.write( "1st: -1
\n" ); document.write( "2nd: +1
\n" ); document.write( "3rd: 3
\n" ); document.write( "---
\n" ); document.write( "Check:
\n" ); document.write( "2(-1)+2(1)+3(3) = 9
\n" ); document.write( "checks
\n" ); document.write( "==============
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
\n" ); document.write( "
\n" );