document.write( "Question 398132: Find three consecutive odd integers such that the sum of twice the first, twice the second, and three times the third is 9. An explanation would be great too! \n" ); document.write( "
Algebra.Com's Answer #282113 by ewatrrr(24785)\"\" \"About 
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\n" ); document.write( "Hi
\n" ); document.write( "consecutive odd integers differ by two
\n" ); document.write( "Let x, (x+2),(x+4) represent the three consecutive odd integers
\n" ); document.write( "Question states***Write as we Read
\n" ); document.write( " 2x + 2(x+2) + 3(x+4) = 9
\n" ); document.write( "solving for x
\n" ); document.write( " 2x + 2x+4 + 3x+12 = 9
\n" ); document.write( " 7x + 16 = 9
\n" ); document.write( " 7x = -7
\n" ); document.write( " x = -1 the three consecutive odd integers are: -1, 1, 3\r
\n" ); document.write( "\n" ); document.write( "CHECKING our Answer***
\n" ); document.write( " -2 + 2 + 9 = 9 \n" ); document.write( "
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