document.write( "Question 397952: Decide whether or not this equation has a circle as its graph. If it does, give the center and the radius.
\n" ); document.write( "8x^2+40x+8y^2+24y-60=0
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Algebra.Com's Answer #281964 by Tatiana_Stebko(1539)\"\" \"About 
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(8x^2+40x)+(8y^2+24y)-60=0
\n" ); document.write( "8(x^2+5x)+8(y^2+3y)-60=0
\n" ); document.write( "8((x^2+2*(5/2)x+(5/2)^2)-(5/2)^2)+8((y^2+2*(3/2)y+(3/2)^2)-(3/2)^2)-60=0(/8)
\n" ); document.write( "(x+(5/2))^2-(25/4)+(y+(3/2))^2-(9/4)-7.5=0
\n" ); document.write( "(x+2.5)^2+(y+1.5))^2=16
\n" ); document.write( "\"%28x-a%29%5E2%2B%28y-b%29%5E2=R%5E2\" has a circle as a graph with center in (a;b) and radius R
\n" ); document.write( "so (x+2.5)^2+(y+1.5)^2=16 has a circle as a graph with center in (-2.5;-1.5) and radius R=4
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