document.write( "Question 397939: My other algebra 2 question is find the value of x. Area of the rectangle=40ft2. xft and (x+3). How do u solve it? \n" ); document.write( "
Algebra.Com's Answer #281943 by josmiceli(19441)\"\" \"About 
You can put this solution on YOUR website!
One side is \"x\" ft
\n" ); document.write( "The other side is \"x%2B3\" ft
\n" ); document.write( "\"A+=+x%2A%28x%2B3%29\"
\n" ); document.write( "given:
\n" ); document.write( "\"A+=+40\" ft2
\n" ); document.write( "------------
\n" ); document.write( "\"40+=+x%2A%28x%2B3%29\"
\n" ); document.write( "\"40+=+x%5E2+%2B+3x\"
\n" ); document.write( "\"x%5E2+%2B+3x+-+40+=+0\"
\n" ); document.write( "Now you can use the quadratic formula:
\n" ); document.write( "\"x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+\"
\n" ); document.write( "\"a++=1\"
\n" ); document.write( "\"b+=+3\"
\n" ); document.write( "\"c+=+-40\"
\n" ); document.write( "\"x+=+%28-3+%2B-+sqrt%28+3%5E2-4%2A1%2A%28-40%29+%29%29%2F%282%2A1%29+\"
\n" ); document.write( "\"x+=+%28-3+%2B-+sqrt%28+9+%2B+160+%29%29%2F2+\"
\n" ); document.write( "\"x+=+%28-3+%2B-+sqrt%28+169+%29%29%2F2+\"
\n" ); document.write( "\"x+=+%28-3+%2B+13%29%2F2\"
\n" ); document.write( "\"x+=+5\" ft answer
\n" ); document.write( "and
\n" ); document.write( "\"x+=+%28-3+-+13%29%2F2\"
\n" ); document.write( "\"x+=+-8\" (can't use the negative root)
\n" ); document.write( "also,
\n" ); document.write( "\"x+%2B+3+=+8\"
\n" ); document.write( "\"A+=+5%2A8\"
\n" ); document.write( "\"A+=+40\" ft2\r
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