document.write( "Question 397870: I did the following problem, but I am not certain I did it correctly. I am hoping a tutor can double check this for me, and put me on the right path if it is wrong. Any help would be greatly appreciated! Here is the problem:\r
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document.write( "Find f^-1(x) \r
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document.write( "f(x)= (2x-3)/(x+1)\r
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document.write( "Here's how I did it:\r
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document.write( "f(x)=2x-3/(x+1)\r
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document.write( "y=2x-3/(x+1)\r
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document.write( "x=(2y-3)/(y+1)\r
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document.write( "xy= (2y-3)/(y+1)*y\r
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document.write( "xy= 2y-3\r
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document.write( "xy-2y=-3\r
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document.write( "y(x-2)/(x-2)=-3/(x-2)\r
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document.write( "y=-3/(x-2)\r
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document.write( "so f^-1(x)= -3/(x-2)\r
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document.write( "Ok...Is this correct, or do I need to go back to the drawing board? Could someone please show me how to check these? Thank you!\r
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Algebra.Com's Answer #281928 by Alan3354(69443)![]() ![]() You can put this solution on YOUR website! I did the following problem, but I am not certain I did it correctly. I am hoping a tutor can double check this for me, and put me on the right path if it is wrong. Any help would be greatly appreciated! Here is the problem:\r \n" ); document.write( "\n" ); document.write( "Find f^-1(x) \r \n" ); document.write( "\n" ); document.write( "f(x)= (2x-3)/(x+1)\r \n" ); document.write( "\n" ); document.write( "Here's how I did it:\r \n" ); document.write( "\n" ); document.write( "f(x)=2x-3/(x+1)\r \n" ); document.write( "\n" ); document.write( "y=2x-3/(x+1)\r \n" ); document.write( "\n" ); document.write( "x=(2y-3)/(y+1)\r \n" ); document.write( "\n" ); document.write( "xy= (2y-3)/(y+1)*y\r \n" ); document.write( "\n" ); document.write( "xy= 2y-3 ****** That won't work.\r \n" ); document.write( "\n" ); document.write( "xy-2y=-3\r \n" ); document.write( "\n" ); document.write( "y(x-2)/(x-2)=-3/(x-2)\r \n" ); document.write( "\n" ); document.write( "y=-3/(x-2)\r \n" ); document.write( "\n" ); document.write( "so f^-1(x)= -3/(x-2)\r \n" ); document.write( "\n" ); document.write( "Ok...Is this correct, or do I need to go back to the drawing board? Could someone please show me how to check these? Thank you! \n" ); document.write( "----------------- \n" ); document.write( "x=(2y-3)/(y+1) \n" ); document.write( "x(y+1) = 2y-3 \n" ); document.write( "xy+x = 2y-3 \n" ); document.write( "xy - 2y = -x-3 \n" ); document.write( "y(x-2) = -x-3 \n" ); document.write( "y = (-x-3)/(x-2) \n" ); document.write( "y = -(x+3)/(x-2)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |