document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=397896>Question 397896</A>: <I><SPAN STYLE=\"word-break: break-all;\"> In the triangle abc, |ab|=12cm, bc=10cm, <bac=30 degrees. Find the remaining angles of the two possible triangles.\r<BR>\n" );
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document.write( "Thank you </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #281896 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=281896\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> In the triangle abc, |ab|=12cm, bc=10cm, <bac=30 degrees. Find the remaining angles of the two possible triangles.<BR>\n" );
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document.write( "|ab| ??  ab might be negative?<BR>\n" );
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document.write( "Law of Sines:<BR>\n" );
document.write( "10/sin(30) = 12/sin(C)<BR>\n" );
document.write( "C = arcsin(0.6)<BR>\n" );
document.write( "C =~ 36.87º<BR>\n" );
document.write( "B = 113.13º<BR>\n" );
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document.write( "C =~ 143.13º<BR>\n" );
document.write( "B = 6.87º\r<BR>\n" );
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