document.write( "Question 397512: find three consecutive odd integers such that twice the sum of the first and third exceeds the second by fifteen. \n" ); document.write( "
Algebra.Com's Answer #281883 by ewatrrr(24785)\"\" \"About 
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\n" ); document.write( "Hi
\n" ); document.write( "Let x, (x+2),(x+4) represent the three consecutive odd integers
\n" ); document.write( "Question states***
\n" ); document.write( " 2[x + (x+4)] = (x+2) + 15
\n" ); document.write( "solving for s
\n" ); document.write( " 4x + 8 = x + 17
\n" ); document.write( " 3x = 9
\n" ); document.write( " x = 3 The three consecutive odd integers are 3,5,7\r
\n" ); document.write( "\n" ); document.write( "CHECKING our Answer***
\n" ); document.write( " 2(3+7) = 20 = 5 + 15 \n" ); document.write( "
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