document.write( "Question 43184: How do you solve for n in p=x+(n-2)y \r
\n" ); document.write( "\n" ); document.write( "I need to see each step on how to solve this. And it would be nice if you could explain why you did each step. Thank you very much.
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Algebra.Com's Answer #28184 by Nate(3500)\"\" \"About 
You can put this solution on YOUR website!
\"p+=+x+%2B+%28n-2%29y\"
\n" ); document.write( "\"p+-+x+=+x+-+x+%2B+%28n-2%29y\" because 2 = 2 can be: 2 - 2 = 2 - 2 as 0 = 0
\n" ); document.write( "\"p+-+x+=+%28n+-+2%29y\"
\n" ); document.write( "\"%28p+-+x%29%2Fy+=+%28n+-+2%29y%2Fy\" you need to remove the \"y\" so it is not distributed
\n" ); document.write( "\"%28p+-+x%29%2Fy+=+n+-+2\"
\n" ); document.write( "\"%28p+-+x%29%2Fy+%2B+2+=+n+-+2+%2B+2\"
\n" ); document.write( "\"%28p+-+x%29%2Fy+%2B+2+=+n\"
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