document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=43179>Question 43179</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A motorcycle daredevil is planning a stunt to perform at a county fair. A ramp must be built to give him a 20% grade, or slope. If the vertical height at the end of the ramp must be 11 ft to assure that the stunt is a success, what must be the length of the horizontal run?\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #28182 by </B><A HREF=/tutors/aboutme.mpl?userid=Nate><B>Nate(3500)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Nate><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=28182\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Slope: 20% of 90 = (2/10)90 = 18<BR>\n" );
document.write( "Sin(18 degrees) = 11/x<BR>\n" );
document.write( "x = 11/Sin(18<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=pi ALIGN=MIDDLE  ALT=\"pi\"   DISABLED_style= \"max-width:90%; height:auto;\" >/180) = 36 ft </SPAN>\n" );
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