document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=397760>Question 397760</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Juniors boat will go 15 miles per hour in still water. If he can go 12 miles downstream in the same amount of time as it takes to go 9 miles upstream, then what is the speed of the current.\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #281812 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=281812\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Juniors boat will go 15 miles per hour in still water. If he can go 12 miles downstream in the same amount of time as it takes to go 9 miles upstream, then what is the speed of the current. \r<BR>\n" );
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document.write( "let x = speed of current<BR>\n" );
document.write( "15+x = speed of boat downstream<BR>\n" );
document.write( "15-x = speed of boat upstream<BR>\n" );
document.write( "distance/speed = time of travel<BR>\n" );
document.write( "time of travel downstream=time of travel downstream<BR>\n" );
document.write( "12/(15+x)=9/(15-x)<BR>\n" );
document.write( "180-12x=135+9x<BR>\n" );
document.write( "21x=45<BR>\n" );
document.write( "x=21/45 mph<BR>\n" );
document.write( "ans: the speed of the current is 21/45 miles per hour </SPAN>\n" );
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