document.write( "Question 397738: Find three consecutive positive even integers such that the product of the second and third integers is twenty more then ten times the first integer. \n" ); document.write( "

Algebra.Com's Answer #281807 by richard1234(7193) $\"\"$ $\"About$

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Let x, x+2, x+4 be the integers, where x is even. Then,\r
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\n" ); document.write( "\n" ); document.write( " $\"%28x%2B2%29%28x%2B4%29+=+20+%2B+10x\"$ \r
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\n" ); document.write( "\n" ); document.write( " $\"x%5E2+%2B+6x+%2B+8+=+20+%2B+10x\"$ \r
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\n" ); document.write( "\n" ); document.write( " $\"x%5E2+-+4x+-+12+=+0\"$ \r
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\n" ); document.write( "\n" ); document.write( " $\"%28x-6%29%28x%2B2%29+=+0\"$ \r
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\n" ); document.write( "\n" ); document.write( "x = 6, -2\r
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\n" ); document.write( "\n" ); document.write( "Checking, both of these satisfy, but the question looks for positive even integers. So {6, 8, 10} are the three integers. \n" ); document.write( "

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