document.write( "Question 397705: A consumer electronics company sells 6.7m MP3 Playerss per month at 100$ a piece. When the price is lowered to 80$ a piece the company sells 10.2m. How many MP3 Players can the company expect to sell per month at a price of 75$ a piece? \n" ); document.write( "
Algebra.Com's Answer #281787 by stanbon(75887)\"\" \"About 
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A consumer electronics company sells 6.7m MP3 Playerss per month at 100$ a piece. When the price is lowered to 80$ a piece the company sells 10.2m. How many MP3 Players can the company expect to sell per month at a price of 75$ a piece?
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\n" ); document.write( "You have two points: (100,6.7m) and (80,10.2m)
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\n" ); document.write( "slope = k = (10.2-6.7)/-20 = -0.175
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\n" ); document.write( "Form: N(x) = kx + b
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\n" ); document.write( "Solve for \"b\":
\n" ); document.write( "6.7m = -0.175*100 + b
\n" ); document.write( "6.7 = -17.5 + b
\n" ); document.write( "b = 24.2
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\n" ); document.write( "N(x) = -0.175x + 24.2
\n" ); document.write( "---
\n" ); document.write( "N(75) = -0.175*75+24.2
\n" ); document.write( "N(75) = 11.075 million
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H. \n" ); document.write( "
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